Quadratic: Standard to Vertex Form
$$x^2+16x+71=0$$
$$x^2+16x+71=0$$
$$degree^\circ=\frac{\pi}{180}$$
$$radian\pi = \frac{180}{\pi}^\circ$$
Use Limit Definition to compute f'(x) when x=-5 $$f(x)=x^2+4x $$
$$2x^3-4x+2 \div x-6 $$
$$\frac{\sec\theta \sin\theta}{\tan\theta+\cot\theta} = \sin^2\theta$$
$$\frac {4p^2+13p-12}{p^3-p^2-2p}$$
$$v^2+6v-59=0$$
$$\frac {-7x+13}{x^2-5x-14}$$
$$\frac {5x-34}{x^2-x-12}$$