Quadratic: Standard to Vertex Form
x^2+16x+71=0
x^2+16x+71=0
degree^\circ=\frac{\pi}{180}
radian\pi = \frac{180}{\pi}^\circ
Use Limit Definition to compute f'(x) when x=-5 f(x)=x^2+4x
2x^3-4x+2 \div x-6
\frac{\sec\theta \sin\theta}{\tan\theta+\cot\theta} = \sin^2\theta
\frac {4p^2+13p-12}{p^3-p^2-2p}
v^2+6v-59=0
\frac {-7x+13}{x^2-5x-14}
\frac {5x-34}{x^2-x-12}